]> $$\begin{array}{rcl}Ai\left(0\right)& =& \frac{1}{3^{\frac{2}{3}}\Gamma \left(\frac{2}{3}\right)}\\ Ai\left(z\right)& =& {\pi }^{-1}\sqrt{\frac{z}{3}}{K}_{\pm \frac{1}{3}}\left(\zeta \right)& ;& \zeta =\frac{2}{3}{z}^{\frac{2}{3}}\\ Ai\left(-z\right)& =& \left(\frac{\sqrt{z}}{3}\right)\left(J_{\frac{1}{3}}\left(\zeta \right)+J_{-\frac{1}{3}}\left(\zeta \right)\right)\end{array}$$