J'v(z)=zv−12v∑k=0∞(−z24)k(v+2k)k!Γ(1+k+v)Y'v(x)=−Γ(−v)cos(vπ)π×zv−12v×∑k=0∞(−z24)k(v+2k)(v+1)kk!−Γ(v)π×2vzv+1×∑k=0∞(−z24)k(2k−v)(1−v)kk!