sbessel4

]> sbessel4

\begin{array}{rcl} i_{n} (z) & = & \sqrt{\frac{π}{2 z}} I_{n + \frac{1}{2}} (z) \\ k_{n} (z) & = & \sqrt{\frac{π}{2 z}} K_{n + \frac{1}{2}} (z) \end{array}